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3x^2/x^2-16=0
Domain of the equation: x^2!=0We multiply all the terms by the denominator
x^2!=0/
x^2!=√0
x!=0
x∈R
3x^2-16*x^2=0
We add all the numbers together, and all the variables
-13x^2=0
a = -13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-13)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-26}=0$
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